x^2-368x+16695=0

Solution for x^2-368x+16695=0 equation:

x^2-368x+16695=0

a = 1; b = -368; c = +16695;
Δ = b2-4ac
Δ = -3682-4·1·16695
Δ = 68644
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{68644}=262$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-368)-262}{2*1}=\frac{106}{2}
=53
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-368)+262}{2*1}=\frac{630}{2}
=315
$